Tribe.net. Local Connections $item.owner.firstName http://CPP.tribe.net/thread/a8c464ea-84bf-45ad-9573-e29cc25e9478#72442175-3036-4bd0-ab46-fc3e9d11a85c 2006-09-05T19:26:35Z 2006-09-05T19:26:35Z

Ah-ha! Beautiful! Thank you very much!

$item.owner.firstName 2006-09-05T19:26:35Z Scott http://CPP.tribe.net/thread/a8c464ea-84bf-45ad-9573-e29cc25e9478#2c8a43a8-43a3-4179-9573-c7ef4c621d87 2006-09-04T17:39:51Z 2006-09-04T17:39:51Z

1, 10000, and 200000 are all integers, so the math is done using integers. Then the result (0) is converted to a double when assigned to 'test' It needs to look like this: test = (1.0 / 10000.0) + (1.0 / 200000.0); If you are using variables, make sure they are cast to doubles, for example: int i = 10000; test = 1.0 / (double)i;

Scott 2006-09-04T17:39:51Z $item.owner.firstName http://CPP.tribe.net/thread/a8c464ea-84bf-45ad-9573-e29cc25e9478#61339422-e345-4fe7-aaa6-548597cf39ad 2006-09-04T16:57:37Z 2006-09-04T16:57:37Z

I'm writing a few short programs based on calculating factors in electronics. As such, I often have to multiply and divide some small numbers, and the round-off is of such a magnitude that it renders the calculations useless. For instance, with this fragment of code: #include <iostream> using namespace std; int main () { double test; test = ( 1 / 10000) + ( 1 / 200000); cout >> test; return 0; } The output will give me zero.

$item.owner.firstName 2006-09-04T16:57:37Z